I wish they had a better picture of the D5.

[jrtom]

http://commons.wikimedia.org/wiki/Dice_by_number_of_sides

Having a little trouble visualizing that.

I have one of those D34s. I have no idea when or where I acquired it; I suspect it was accidental (i.e., used to be someone else's and ended up in my dice bag).

Comments

Re: d2 lol :)

[amnesiadust.livejournal.com]

Maybe, but it seems like a huge pain in the ass. The obvious things don't work. For instance, 2d3 is not the same as 1d6; the distributions are different. Nor is 1d2*1d3 the same as 1d6, for the same reason. You would have to use the d2 as one "digit" and the d3 as the other, build a grid of values (1, 2, 3 / 4, 5, 6) and translate the values of the d2 and the d3 to give you the correct number. I think that generalizes to an arbitrarily large number of factors, but there is no unique such scheme either, so the GM would have to arbitrate all the rolls.

In short, if the person is gonna be that esoteric I guess I can't stop them, and indeed that may be the fun part for them... but unless they're some kind of savant or have had a lot of practice, gaming with them would be pretty slow.

Re: d2 lol :)

[jrtom.livejournal.com]

The expression for combining two dice is pretty simple, isn't it?

Let's say that d_2 is the value that the d2 gives you (in {1,2}). Then to get d_6:

(d_2 - 1)*3 + d_3

or, in general,

(d_i - 1)*j + d_j

It's just a very slight generalization of what you do to use two d10s to give you a d100.

I think the further generalization to n dice should be straightforward. If I had a couple of minutes, I'd work it out now.

Re: d2 lol :)

[amnesiadust.livejournal.com]

Nah, I see it. Was just being obtuse. And thinking about hot sword-forging chicks. :P

Re: d2 lol :)

[jrtom.livejournal.com]

I just saw that post. I can understand.

Feel like posting a link to her profile? This I gotta see. :)